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分解因式:a^3-a,b^2(x-3)+b^2(3-x),16(m-n)^2-9(m+n)^2,4x^2(x-y)+(y-x),4-x^2-4xy-4y^2.计算:(x-y+2)(x+y+2),(3x-2y-1)(3x+2y+1),-4x^3y*[7x^2y-3xy+(2xy)^3].先化简再求值:x(2x+1)(1-2x)-4x(x-1)(1-x),其中x=-1/2.解二元一次方程组:式子一:y/3-y/2=1,式子二:2x+3y=-2.填空:若m^2-2m+n^2+4n=-5,则m+n=?,已知方程组3x+2y=m+2,2x+3y=m的解适合x+y=8,则m=?.以上就是题目,还要规范,
人气:468 ℃ 时间:2019-08-21 20:58:34
解答
a^3-a=a(a^2-1)=a(a-1)(a+1)b^2(x-3)+b^2(3-x)=b^2(x-3)-b^2(x-3)=016(m-n)^2-9(m+n)^2=[4(m-n)-3(m+n)][4m-4n+3m+3n]=(4m-4n-3m-3n)(7m-n)=(m-7n)(7m-n)4x^2(x-y)+(y-x)=4x^2(x-y)-(x-y)=(4x^2-1)(x-y)=(2x-1)(2x...
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