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计算(3a+2)*(3a-2)*-(2a+3)*(2a-3)*
*是平方啊,打错了......
人气:401 ℃ 时间:2020-04-12 02:28:39
解答
65(a^4-1)过程??[(3a+2)(3a-2)]^2-[(2a+3)(2a-3)]^2=(9a^2-4)^2-(4a^2-9)^2=(13a^2-13)(5a^2+5)=65(a^2-1)(a^2+1)=65(a^4-1)
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