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初二数学上册习题15.2
{2x-y-3}的2次方
人气:198 ℃ 时间:2020-02-18 09:29:04
解答
(2x-y-3)^2={2x-(y+3)}^2
=4x^2-4x(y+2)+(y+3)^2
=4x^2+y^2-4xy-8x+6y+9谢了顺便帮我解{x+y+1}{x+y-1}{x+y+1}{x+y-1}={(x+y)+1}{(x+y)-1}=(x+y)^2-1=x^2+y^2+2xy-1
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