m1g |
k1 |
处于拉伸状态时的拉伸量为:x2=
m2g |
k1 |
开始平衡时,劲度系数为k2的轻弹簧处于压缩状态,压缩量为:x3=
m1g+m2g |
k2 |
物块2重力势能增加了:m2gx3=m2g×
m1g+m2g |
k2 |
(m1+m2) |
k2 |
物块1重力势能的增加量为:m1g(x1+x2+x3)=m1(m1+m2)g2(
1 |
k1 |
1 |
k2 |
故答案为:m2g2
(m1+m2) |
k2 |
1 |
k1 |
1 |
k2 |
m1g |
k1 |
m2g |
k1 |
m1g+m2g |
k2 |
m1g+m2g |
k2 |
(m1+m2) |
k2 |
1 |
k1 |
1 |
k2 |
(m1+m2) |
k2 |
1 |
k1 |
1 |
k2 |