一只船第一次顺流航行32千米,逆流航行16千米,共用8小时,第二次用16小时,顺流航行24千米,逆流航行20千米,问这只小船在静水中的船速和水速各是多少
人气：188 ℃ 时间：2020-05-19 23:35:24
解答
设船在静水中速度为xkm/h,水速为ykm/h
则顺流航行速度为(x+y)km/h,逆流航行速度为(x-y)km/h
由已知条件,列方程
32/(x+y)+16/(x-y)=8
24/(x+y)+20/(x-y)=16
解出
x=-14/15km/h<0,不知是我算错了,还是题目有错误.
推荐
猜你喜欢
- This firm,forced to leave the Chinese market,has not kept the written promise____made before
- The way people act in private is often different from ____ they act in public.
- Everybody have a dream ,my dream is to travel around the World. When i old我翻译的有没有错
- 一切物体都具有___.同一物体,它的温度___时,分子无规则运动___,内能___.
- 在一个密闭容器中发生如下反应,2SO2+O2——2SO3,反应过程中某一刻测得,他们的浓度都为0.2mol/L.
- You should wear uniforms at school改为同义句 You____ ____ _____wear uniforms at shool
- If there were a big fire in your building,what would you do（如果你的住房着火了,你会怎么办?）
- 函数y=f(x)的定义域为（0,正无穷大）,且对定义域内的任意x,y都有f(xy）=f（x)+f(y),且f(2)=1
