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数学
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解不等式|x2-4x+8|+|x-3|≤5
人气:298 ℃ 时间:2020-04-20 07:06:57
解答
|x2-4x+8|+|x-3|=|(x-2)²+4|+|x-3|
当X>3时,不等式为(x-2)²+4+x-3≤5
x(x-3)≤0
0≤x≤3
∴x不存在
当x≤3时,不等式为x²-4x+8+3-x≤5
(x-2.5)²≤1/4
-1/2≤x-2.5≤1/2
2≤x≤5
∴2≤x≤3
综上所述 2≤x≤3
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