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解不等式log(0.5)(x2-5x-6)>log(2)(1/2(x+6))
人气:125 ℃ 时间:2020-06-02 08:06:59
解答
log(0.5)(x²-5x-6)>log2(1/2(x+6))
log2[1/(x²-5x-6)]>log2[1/2(x+6)]
1/(x²-5x-6)>1/2(x+6)
x²-5x-6<2(x+6)
x²-7x-18<0
(x-9)(x+2)<0
-2x²-5x-6>0
(x-6)(x+1)>0
-12(x+6)>0
x>-6
综合起来
-10-10x<-1 或x>62(x+6)>0 x>-6(x-9)(x+2)<0-2
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