(a+b）^2-16a^2(x^2+4)^2-4x^2m^4-2m^2n^2+n^4(x^2-x)^2+1/2（x^2\x)+1/_数学解答

(a+b）^2-16a^2
(x^2+4)^2-4x^2
m^4-2m^2n^2+n^4
(x^2-x)^2+1/2（x^2\x)+1/16
4m^2-n^2-6n-9
2a-4b+a^2-4b^2
(3a+b)^2-12ab
(m-1)(m-3)+1
x^2(x^2-2)+1
-x^2-12xy-20y^2
3x^2-11xy+10y^2
2(a-1)-11(a-1)+12
9a^4-7a^2+1
a^4+a^2b^2+b^4
第4题是（x^2-x)^2+1/2（x^2-x)+1/16

人气：155 ℃　时间：2020-02-02 09:44:30

解答

(a+b）^2-16a^2=a^2+2ab+b^2-16a^2=b^2+2ab-15a^2=(b+5a)(b-3a)(x^2+4)^2-4x^2=(x^2+4)^2-(2x)^2=(x^2+2x+4)(x^2-2x+4)m^4-2m^2n^2+n^4=(m^2-n^2)^2=(m+n)^2(m-n)^2第4题是不是打错了,后一个括号里应该是减号吧：(x^...