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1.已知x:y=2:3,且2x+y/2-1=x-y/3,求x,y的值.2.已知x,y的值满足等式x+1/2=y+3/4=x+y/5,求式子
3x+2y+1/x+2y+3的值.急用!
人气:310 ℃ 时间:2020-04-11 21:25:23
解答
1,x:y=2:3那么x=2/3y2x+y/2-1=x-y/3即2*2/3y+y/2-1=2y/3-y/3即4y/3+y/2-1=y/3即4y/3+y/2-y/3=1y=2/3,x=4/92,x+1/2=y+3/4=x+y/5即5(x+1)=2(x+y)2(x+1)=y+3那么y=7,x=43x+2y+1/x+2y+3=9/7
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