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一元二次方程(1)x^2-6x+2=0 (2)2x^-6x+1=0
要过程
人气:377 ℃ 时间:2020-10-02 02:08:21
解答
x^2-6x+2=0
x^2-6x+9=7
(x-3) ^2=7
x-3=±√7
x=3±√7
2x^-6x+1=0
2(x^-3x)+1=0
2(x^-3x+2.25)+1--4.5=0
2(x-1.5)^2=3.5
(x-1.5)^2=1.75
x-1.5=±√7/2
x=(3±√7)/2
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