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(a-b/a+b)2x3a+3b/2a-2b-a2-b2/a2除以b分之a
人气:297 ℃ 时间:2020-05-08 01:49:35
解答
(a-b/a+b)2x3a+3b/2a-2b-a2-b2/a2除以b分之a=[2(a-b)/(a+b) * (3a+3b)/(2a-2b)-(a2-b2)/a2 ]÷a/b=[2(a-b)/(a+b)*3(a+b)/2(a-b)-(a2-b2)/a2 ]÷a/b=[3-(a-b)/a ]÷a/b=[(3a-(a-b))/a]÷a/b=(b+2a)/a *b/a=(b^2+2ab)/...
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