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1.x+1分之x-1减去x²-1分之4=x+1分之x+2
2.x²+x分之7+x²-x分之3=x²-1分之6
3.x+1分之2+x-1分之3=x²-1分之6
4.x-2分之2+x²-4分之1=x+2分之3
0.0不好意思哈~是四道~
人气:241 ℃ 时间:2020-07-06 07:07:29
解答
1.x+1分之x-1减去x²-1分之4=x+1分之x+2
(x-1)/(x+1) - 4/(x²-1)=(x+2)/(x+1)
同时乘以x²-1得
(x-1)²-4=(x+2)(x-1)
整理得
x²-2x-3=x²+x-2
解得x=-1/3剩下的呢~~2.x²+x分之7+x²-x分之3=x²-1分之67/(x²+x) + 3/(x²-x)= 6/(x²-1)乘以x(x²-1)得7(x-1) + 3(x+1)=6x整理得7x-7+3x+3=6x解得x=13.x+1分之2+x-1分之3=x²-1分之62/(x+1) +3/(x-1)=6/(x²-1)乘以x²-1得2(x-1)+3(x+1)=6整理得2x-2+3x+3=6解得x=14.x-2分之2+x²-4分之1=x+2分之32/(x-2)+1/(x²-4)=3/(x+2)乘以x²-4得2(x+2)+1=3(x-2)整理得2x+4+1=3x-6解得x=11
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