证明：∵(a^2-b^2)^2+(a^2-c^2)^2+(b^2-c^2)≥0∴a^4+b^4+c^4≥a^2b^2+a^2c^2+b^2c^2∴a^4+b^4+c^4-abc(a+b+c)=(2a^4+2b^4+2c^4-2a^2bc-2ab^2c-2abc^2)/2≥(a^4+b^4+c^4+a^2b^2+a^2c^2+b^2c^2-2a^2bc-2ab^2c-2abc^2)...