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对y=sin²(2t-5)求导
人气:298 ℃ 时间:2020-05-22 11:57:40
解答
利用复合函数的求导法则:
y'=2sin(2t-5)·[sin(2t-5)]'
=2sin(2t-5)·cos(2t-5)·(2t-5)'
=sin(4t-10)·2
=2sin(4t-10)
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