一道英文物理题 十分感激
On their wedding day,my father gave my mother a gold ring.It weighed 3.70g.On their golden wedding anniversary fifty years later,it weighed 3.30g.How many atoms were lost each second,on average,from the ring during that time?The mass of a gold atom is 3.29 乘以10的负27次方kg.There are 86400 seconds in a day and 365.days in a year.
人气:275 ℃ 时间:2020-08-26 02:52:40
解答
金,Au,相对原子量197 n=0.4/197*NA=0.4/197*6.02×10^2350年=50*365*24*3600秒 两者除一下就可以得到答案 7.75*10^11NA是阿伏伽德罗常数,你应该知道.题目的大意是在结婚的时候爸爸送妈妈一枚3.7g的金戒指,50年后金戒...是的,题目是这个意思。The mass of a gold atom is 3.29 乘以10的负27次方kg. 这个数字是什么意思呀?这个答案用到了吗?还有n是什么意思呢?阿伏伽德罗常数是什么呀?不好意思啊, 物理搁置了好多年没有学,现在又要开始学,以前学的都忘了。
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