> 数学 >
x^2-2x
(x+2)^2-(x+2)
(a+b)^2-4(a+b)+3
6x^2-1
-20x^2-x+1
14a^-9ab+b^2
用十字相乘法分解
人气:485 ℃ 时间:2020-09-26 06:45:29
解答
(1)x^2-2x=x(x-2)
(2)(x+2)^2-(x+2)=(x+2)(x+2-1)=(x+2)(x+1)
(3)(a+b)^2-4(a+b)+3=(a+b-1)(a+b-3)
(4)6x^2-1=(根号6x+1)(根号6x-1)
(5)-20x^2-x+1=-(20x^2+x-1)=-(4x+1)(5x-1)
(6)14a^-9ab+b^2=(2a-b)(7a-b)
(同意请采纳)第六个打错了应该是
6x^2-x-1
还有两个
x^2-3xy+2y^2
2x^2-7x+3
谢谢6x^2-x-1=(2x-1)(3x+1)

x^2-3xy+2y^2=(x-2y)(x-y)

2x^2-7x+3=(2x-1)(x-3)
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