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y=cosx/(1+sinx)的微分
人气:429 ℃ 时间:2020-06-02 00:45:00
解答
y = cosx/(1+sinx)dy/dx = [(1+sinx)(-sinx)-(cosx)(cosx)]/(1+sinx)²= (-sinx-sin²x-cos²x)/(1+sinx)²= [-sinx-(sin²x+cos²x)]/(1+sinx)²= -(sinx+1)/(1+sinx)²= -1/(1+si...
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