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(tanx)^[1/(cosx-sinx)]当x趋于π/4时,求极限
人气:134 ℃ 时间:2019-12-01 13:08:40
解答
原式=lim(x趋于π/4)e^[lntanx/(cosx-sinx)] …………分子分母同时趋于0,罗必达法则
=lim(x趋于π/4)e^[(1/cos^2xtanx)/(-sinx-cosx)]
=lim(x趋于π/4)e^1/[-sinxcosx(sinx+cosx)]
=e^(-√2)
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