在等比数列{an}中,已知q=2,S4=1,求S8
人气:357 ℃ 时间:2020-09-19 07:24:00
解答
s8=a1(1-q^8)/(1-q)
=a1(1-q^4)(1+q^4)/(1-q)
=(1+q^4)*[a1(1-q^4)/(1-q)]
=(1+q^4)*S4
=(1+2^4)*1
=1+16
=17
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