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有理数除法运算
(-4/3)*(-1又2/1)/(-2又4/1)
-6*(-0.25)*14/11
-9*(-11)/3/(-3)
人气:382 ℃ 时间:2020-04-02 06:11:27
解答
(-4/3)*(-1又2/1)/(-2又4/1)
=(-4/3)*(-3/2)/(-9/4)
=(-4/3)*(-3/2)*(-4/9)
=-8/9
-6*(-0.25)*14/11
=-1.5*14/11
=-3/2*14/11
=-21/11=-1又10分之10
-9*(-11)/3/(-3)
=99/3/(-3)
=-11
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