化简sin(2π-α)cos(3π+α)cos(3/2π+α)/sin(-π+α)sin(3π-α)cos(-α-π)._其他解答

化简sin(2π-α)cos(3π+α)cos(3/2π+α)/sin(-π+α)sin(3π-α)cos(-α-π)
.

人气：289 ℃　时间：2020-06-16 22:47:06

解答

sin(2π-α)cos(3π+α)cos(3/2π+α)/sin(-π+α)sin(3π-α)cos(-α-π)
=(-sinα)(-cosα)sinα/(-sinα)sinα(-cosα)
=1