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数学
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三元一次方程:x+y-z=0 x+2y+z=13 2x-3y+2z=5
x+y-z=0
x+2y+z=13
2x-3y+2z=5
人气:249 ℃ 时间:2020-03-29 19:30:47
解答
x+y-z=0 (1)
x+2y+z=13 (2)
2x-3y+2z=5 (3)
由(1)+(2),2(1)+(3)得
2x+3y=13 4x+6y=26
4x-y=5 4x-y=5
x=2 y=3
z=x+y=5
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