4x^2+2y+10=-y^2+12x
4x^2+2y+10+y^2-12x=0
(4x^2-12x+9)+(y^2+2y+1)=0
（2x-3)^2+(y+1)^2=0
所以 2x-3=0,y+1=0
x=3/2, y= -1
(x)^2y=(3/2)^-2=(2/3)^2=4/9