_a表示底数,()里是真数设y = (1/2)^[log_2 (3)]log_(1/2) (y) = log_2 (3)log(y) / log(1/2) = log(3) / log(2),换底公式log(y) / -log(2) = log(3) / log(2)-log(y) = log(3)log(1/y) = log(3)1/y = 3y = 1/3∴(1/2...