若有一个圆的极坐标方程是p=5cosa-5根号3sina,则其圆心坐标与半径分别是
人气:231 ℃ 时间:2019-10-23 16:35:56
解答
设该圆一动点为(x,y)
则 p^2=x^2+y^2
pcosa=x psina=y
原条件左右同时乘以p
得 x^2+y^2=5x+5根3y
(x-5/2)^2+(y-5根3/2)^2=25
所以 圆心(5/2,5根3/2) 半径5
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