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X/(X^2-3X+1)=7,求X^2/(X^4+5X^2+1)的值
人气:490 ℃ 时间:2020-04-16 10:36:41
解答
X/(X^2-3X+1)=7
(x²-3x+1)/x=1/7
即x-3+1/x=1/7
x+1/x=22/7
(x^4+5x²+1)/x²
=x²+5+1/x²
=(x+1/x)²+3
=(22/7)²+3
=631/49
∴X^2/(X^4+5X^2+1)=49/631
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