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求化简(sinx+tanx)/cos^2x+sin^2x+cosx
人气:321 ℃ 时间:2020-04-06 12:15:28
解答
(sinx+tanx)/(cos^2x+sin^2x+cosx)
=(sinx+sinx/cosx)/(1+cosx)
=sinx(cosx+1)/[cosx(1+cosx)]
=sinx/cosx
=tanx
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