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y=tan(x^2+e^x+ln7),求dy
人气:296 ℃ 时间:2020-10-01 18:47:03
解答
∵y=tan(x^2+e^x+ln7)
∴dy=d(tan(x^2+e^x+ln7))
=(sec(x^2+e^x+ln7))^2*d(x^2+e^x+ln7)
=(sec(x^2+e^x+ln7))^2*(2x+e^x)dx.
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