1/x+7=[x+1/(2x-1)(x+7)]+(1/2x*2-3x+1)1/x+7 = [x+1/(2x-1)(x+7)]+ 1/[（2X-1)(X-1) ]1/x+7 = [(x+1)(x-1)/(2x-1)(x+7)(x-1)]+ [(X+7)/（2X-1)(X-1)(x+7)]1/x+7 = [(x+1)(x-1)+X+7]/(2x-1)(x+7)(x-1)因为X+7不等于0...