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数学
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(x+3y-2z)(x-3y-2z)-(x+3y-2z)^2 要过程
还有一道:
填空:(x-y+1)(x+y-5)=(x-y-2+_____)(x+y-2-_____)=[(x-2)-(____)]*[(x-2)+(____)]=(____)^2-(____)^2=_________
人气:164 ℃ 时间:2020-01-25 16:28:39
解答
(x+3y-2z)(x-3y-2z)-(x+3y-2z)^2
=(x+3y-2z)[(x-3y-2z)-(x+3y-2z)]
=(x+3y-2z)(-6y)
=-6xy-18y²+12yz(x+3y-2z)^2的平方呢提取公因式(x+3y-2z)另一个因式是[(x-3y-2z)-(x+3y-2z)](x-y+1)(x+y-5)=(x-y-2+3)(x+y-2-3)=[(x-2)-(y-3)]*[(x-2)+(y-3)]=(x-2)^2-(y-3)^2=x²-4x-y²+6y-5
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(x+3y-2z)(x-3y-2z)-(x+3y-2z)^2
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