因为2(x-1/2)²+|y-1|=0
所以x-1/2=0且y-1=0
x=1/2, y=1
所以
3B-2A
=3(2x²-3xy-2y²)-2(3x²-xy+y²)
=6x²-9xy-6y²-6x²+2xy-2y²
=(6x²-6x²)+(-9xy+2xy)+(-6y²-2y²)
=-7xy-8y²
=-7×(1/2)×1-8×1²
=-7/2-8
= -23/2