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x-1分之1+1+x分之1 a²-1分之a+a²-1分之3a+1+1-a²分之2a+3
还有一道是8-2x分之x²-16 其中x=-2
人气:433 ℃ 时间:2019-08-21 11:30:19
解答
(1) 1/(x-1)+1/(1+x)
=2x/(x^2-1)
(2) a/(a²-1)+(3a+1)/(a²-1)+(2a+3)/(1-a²)
=(a+3a+1-2a-3)/(a^2-1)
=2(a-1)/(a^2-1)
=2/(a+1)
(3) (x²-16 )/(8-2x)
=-(x+4)(x-4)/[2(x-4)]
=-(x+4)/2
=-(-2+4)/2
=-1
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