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f(x)=(x^2-3x+2/x^2-x-2)^2 求它的反函数
人气:275 ℃ 时间:2019-12-11 01:19:24
解答
令f(x)=y (看起来方便一点)y=(x^2-3x+2/x^2-x-2)^2 =[(x-1)(x-2)/(x+1)(x-2)]^2y=[(x-1)/(x+1)]^2√y=(x-1)/(x+1) 或-√y=(x-1)/(x+1)√y×(x+1)=(x-1)√yx+√y-x=-1(1-√y)x=(1+√y)x=(1+√y)/(1-√y)或-√y×(x+1...
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