[﹙x-1)分之x+(x+1)分之1]÷(xˆ2－2x＋1)分之(x＋1)
=[(x-1)(x+1)]分之(x²+2x-1) * (x+1)分之(x-1)²
=(x+1)²分之[(x²+2x-1)(x-1)]
当x=-2
原式
=(x+1)²分之[(x²+2x-1)(x-1)]
=(-1)²分之[(4-4-1)(-2-1)]
=3