若丨ab-2丨+丨a-2丨=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)的值由丨ab-2丨+丨a-2丨=0,得ab=2,a=2,b=1；故1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)=1/2+1/(3×2)+1/(4×3)+.+1/(20...