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分解因式:(1+y)²-2x²(1-y²)+x的4次方(1-y)²
人气:169 ℃ 时间:2020-04-14 15:49:18
解答
=(1+y)²-2(1+y) ×x²(1-y) +[x²(1-y)]²
=[(1+y)-x²(1-y)]²
=(1+y-x²+x²y)²
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