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因式分解(xy-1)²+(x+y-2)(x+y-2y)怎么做哇?
人气:458 ℃ 时间:2020-02-04 07:40:02
解答
最后一项是否多了一个y?如果没有那个y,就应当是
(xy-1)²+(x+y-2)(x+y-2)
=(xy-1+x+y-2)(xy-1-x-y+2)
=(xy+x+y-3)(xy-x-y+1)对不起啊,真的打错了正确的是:(xy-1)²+(x+y-2)(x+y-2xy)少了个x,帮忙解解。原式=x^2y^2-2xy+1+(x+y)^2-2(x+y)-2xy(x+y)+4xy=x^2y^2+2xy+1+(x+y)^2-2(x+y)=(xy+1)^2-2(x+y)+(x+y)^2=(xy+1-x-y)^2
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