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求函数y=根号下1-sinx+根号下1+sinx的周期
人气:130 ℃ 时间:2020-03-28 16:57:23
解答
y=根号下(sin^2(x/2)-2sin(x/2)cos(x/2)+cos^2(x/2))+根号下(sin^2(x/2)+2sin(x/2)cos(x/2)+cos^2(x/2))=根号下【(sin(x/2)-cos(x/2))^2】+根号下【(sin(x/2)+cos(x/2))^2】=|sin(x/2)-cos(x/2)|+|si...为什么是2/x二倍角公式啊sinx=sin2(x/2)=2sin(x/2)cos(x/2)
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