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lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
人气:311 ℃ 时间:2020-01-30 10:42:54
解答
lim [(n+3)/(n+1)]^(n-2)
=lim [1+2/(n+1)]^(n-2)
=lim {[1+2/(n+1)]^[(n+1)/2]}^[(n-2)×2/(n+1)]
=lim e^[2(n-2)/(n+1)]
=e^lim 2(n-2)/(n+1)
=e^lim [2(1-2/n)/(1+1/n)]
=e²
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