((a²-3a+2分之2a-6)-(a-1分之3)-(2-a分之2)=(2a-6)/(a²-3a+2)-3/(a-1)-2/(2-a)=(2a-6)/[(a-1)(a-2)]-3/(a-1)+2/(a-2)=(2a-6)/[(a-1)(a-2)]-3(a-2)/[(a-1)(a-2)]+2(a-1)/[(a-1)(a-2)]=(2a-6-3a+6+2a-2)/[(a...