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(-1/2x^2y)^-2÷(-2/3xy^2)=?
人气:123 ℃ 时间:2020-06-14 02:18:01
解答
(-1/2x^2y)^-2÷(-2/3xy^2)=1/(1/2x²y)²*1/(-2/3xy²)
=1/(1/4x⁴y²)*1/(-2/3xy²)
=-4*3/2*1/(x⁴y²*xy²)
=-6/(x^5y⁴)
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