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(20又9/4+12.25-31又30/1)除299+9(13又9/1-12.25)*1又31/5(过程详细点)
人气:210 ℃ 时间:2020-01-31 23:01:22
解答
(20又9/4+12.25-31又30/1)÷299+9(13又9/1-12.25)×1又31/5=(9/184+4/49-30/931)×299/1+9(9/118-4/49)×31/36=[(9×20)/(184×20)+(4×45)/(49×45)-(30×6)/(931×6)]×299/1+9[(9×4)/(118×4)-(4×9)/(49×9)]×...
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