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化简:(sinα)^2+(sinβ)^2-(sinα)^2(sinβ)^2+cos2αcos2β
人气:217 ℃ 时间:2020-06-03 02:03:54
解答
sinα=(1-cos2α)/2
(sinα)^2+(sinβ)^2-(sinα)^2(sinβ)^2+cos2αcos2β
=(1-cos2α)/2+(1-cos2β)/2-(1-cos2α)/2*(1-cos2α)/2+cos2αcos2β
=(1+cos2αcos2β)*0.75
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