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a^3-6a^2+12a-8因式分解怎么做?求详解
人气:330 ℃ 时间:2020-10-02 02:35:56
解答
a³-6a²+12a-8
=(a³-6a²+8a)+(4a-8)
=a(a²-6a+8)+4(a-2)
=a(a-2)(a-4)+4(a-2)
=(a-2)(a²-4a+4)
=(a-2)³
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