[(x-2)^3 * (3*x+1)]’
=[(x-2)^3]’ * (3*x+1) + (x-2)^3 * (3*x+1)’
=3*(x-2)^2 * 1 * (3*x+1) + (x-2)^3 * 3
=12*x^3 – 51*x^2 + 60*x - 12