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复数(1+根号下3 i)3次方= ?
人气:125 ℃ 时间:2020-02-18 13:33:39
解答
=(1+2*3^0.5*i-3)*(1+3^0.5*i)
=(-2+2*3^0.5*i)*(1+3^0.5*i)
=-2*(1-3^0.5*i)*(1+3^0.5*i)
=-2*(1+3)
=-8
=[2*(cos60du+isin60du)]^3
=8*(cos180du+isin180du)
=8
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