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数学
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(4又4/ 7‐1又11/ 4)÷(4/ 7+2/ 3)×5/ 6
人气:409 ℃ 时间:2020-09-17 11:22:58
解答
原式=(32/7-15/4)÷(4/7+2/3)*5/6
=(32/7*5/6-15/4*5/6)÷(4/7+2/3)
=(80/21-15/8)÷26/21
=80/21*21/26-15/8*21/26
=40/13-105/104
=320/104-105/104
=215/104
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