tanα=m,π<α<2π,sinα=
人气:123 ℃ 时间:2020-02-04 01:26:47
解答
tanα=sinα/cosα=m
cosα=sinα/m
(sinα)^2+(cosα)^2=1
(sinα)^2+(sinα/m)^2=1
(m^2+1)/m^2*(sinα)^2=1
(sinα)^2=m^2/(m^2+1)
π<α<2π
sinα<0
sinα=-m/(m^2+1)^(1/2)
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