∫sin(5x-π/6)dx=-0.2cos(5x-π/6)+C可以写一下过程嘛？谢谢设t=5x-π/6则∫sin(5x-π/6)dx=∫0.2sin(5x-π/6)d(5x-π/6)=∫0.2sintdt=-0.2cosT+C=-0.2cos(5x-π/6)+C