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(sin2π/3+cos11π/6)tan7π/4=
人气:186 ℃ 时间:2020-09-29 15:11:32
解答
(sin2π/3+cos11π/6)tan7π/4
=[sin(π-π/3)+cos(2π-π/6)]*tan(2π-π/4)
=(sinπ/3+cosπ/6)*(-tanπ/4)
=[(根号3)/2+(根号3)/2]*(-1)
=-根号3
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